Further exercises on permutation groups
I will keep here some additional exercises, mostly suggested to me by
various people.
1. Let G be a transitive permutation group on Ω. Show that, for
any permutation h of Ω, the average number of fixed points of
the elements of the coset Gh is equal to 1.
2. (Antonio Machì, Roma)
A descent
in a permutation g in the symmetric group Sn is
a point i such that ig <= i; it is a strict
descent if ig < i.
Prove that, if a subgroup G of Sn
has h orbits, then
the average number of descents of a permutation in G is
(n+h)/2, and the average number of strict descents is
(n-h)/2. Deduce the Orbit-Counting Lemma.
3. (Antonio Machì, Roma)
(a) Let z(g) be the number of cycles of a permutation
g in Sn, and t(g) the minimum
number of transpositions whose product is g. Prove that
z(g)+t(g)=n.
(b) Prove that, if t1, ..., tk are
transpositions which generate a transitive subgroup of Sn,
then k >= n-1. If, further,
t1...tk=1, then k >= 2n-2
and k is even.
(c) Hence show that, if g1, ..., gm
generate a transitive subgroup of Sn, then
z(g1) + ... + z(gm)
<= (m-1)n+1.
If, further, g1...gm=1, then
z(g1) + ... + z(gm)
<= (m-2)n+2,
and the difference of these two quantities is even.
(d) How should the preceding result be modified if the group generated by
g1, ..., gm has a prescribed number
p of orbits?
(e) Suppose that g1, g2,
g3 generate a regular subgroup G of
Sn, and
g1g2g3=1. Let
z(g1)+z(g2)
+z(g3)=n+2-2g. Prove
Hurwitz's Theorem:
If g > 1 then the order of G is at most 84(g-1).
Construct an example meeting the bound when g=3.
Hint: If gi has order ni for
i=1,2,3, show that
1/n1+1/n2+1/n3
= 1 - 2(g-1)/n,
where n=|G|.
For a crib, see:
A. Machì, The Riemann-Hurwitz formula for the centralizer of a pair of
permutations, Arch. Math. 42 (1984), 280-288.
A. Jacques, Sur le genre d'une paire de substitutions, C.R. Acad. Sci.
Paris 267 (1968), 625-627.
4. Define the automorphism group of a G-space Ω,
and prove that it is equal to the centraliser of G in the
symmetric group on Ω.
If G is transitive on Ω, prove that the automorphism group
of Ω is isomorphic to
NG(Gα)/Gα,
where α is a point of Ω.
5. Let p be a prime congruent to 3 mod 4. Prove that a simple
group of order p(p+1)(p-1)/2 is isomorphic to
PSL(2,p). Hence show that the simple groups PSL(3,2) and PSL(2,7)
are isomorphic.
Hint: Let G be such a group, and P a Sylow
p-subgroup and N its normaliser. Show that
|G:N|=p+1, and that, acting on the cosets of N,
G is a 2-transitive group in which the stabiliser of a point
is isomorphic to the group
x -> a2x+b of permutations
of GF(p) (fixing a point infty).
Now show that the 2-point stabiliser is cyclic of order (p-1)/2,
and its normaliser is dihedral, containing the element
x -> (-1)/x.
Deduce that G is isomorphic to PSL(2,p).
6. This is Iwasawa's Lemma: see K. Iwasawa, Uber die
Einfachkeit der speziellen projektiven Gruppen, Proc. Imp. Acad.
Tokyo 17 (1941), 57-59.
Let G be a permutation group on Ω. Suppose that there is
an abelian normal subgroup A of the stabiliser of a point with the
property that the conjugates of A generate G. Then any
non-trivial normal subgroup of G contains the derived group
G'. In particular, if A is contained in G', then
G is simple.
Prove this, and use it to show that the groups PSL(n,F) are
simple for n>1 (except for PSL(2,2) and PSL(2,3)).
For a crib, see D. E. Taylor, The Geometry of the Classical Groups,
Heldermann, Berlin, 1992. ISBN: 3885380099.
7. For this exercise, recall from pages 33-34 (and 79) of the book that
there are 30 projective planes on a set of 7 points,
falling into two orbits O1 and
O2 of size 15 under the action of the alternating group
A7.
Construct a new geometry with three kinds of elements, "Points", "Lines"
and "Planes", as follows:
- the Points are the elements of O1;
- the Lines are the 3-element subsets of the 7-set;
- the Planes are the elements of O2;
- a Point P and Line ijk are incident if ijk
is a line of P;
- similarly for incidence between Planes and Lines;
- a Point and Plane are incident if they share three lines through a point.
Prove that this geometry is isomorphic to 3-dimensional projective space
over GF(2). (You may find it convenient to define an addition on
the set {0} ∪ O1 by the rules that
P+0 = 0+P = P, P+P = 0, and
P+Q = R whenever P,Q,R are the three Points
incident with a Line. Show that this is an elementary abelian 2-group, using
the existence and structure of the Planes to verify that addition is
associative.)
Deduce that A7 is a subgroup of
PSL(4,2) with index 8. Hence conclude that PSL(4,2) is isomorphic to
A8.
8. Let Pn be the set of all partitions of the set
{1, ..., n}. There is a function C from Sn
to Pn, which maps any permutation to the partition
induced by its cycles.
Prove that the set C(G), for a permutation group G,
determines
- the order of G;
- for each p in Pn, the cardinality of
C-1(p) (the set of elements of G whose
cycle partition is p);
- The cycle index of G.
Note: Eamonn O'Brien
has shown that there are two pairs of groups of order 64 (numbers
19 and 111, and 94 and 249, in the lists in MAGMA and GAP), which act
transivitely on 16 points, such that the two groups in each pair give
rise to the same sets of cycle partitions. So C(G) does
not determine G up to isomorphism. Here is
a GAP program to verify this.
The idea for this exercise came from
Alberto Leporati, Milano.
9. Let G be a group with two subgroups H and K so
that the actions of G on the cosets of H and K are
not permutation isomorphic but have the same permutation character. Let
n be the index of H (or K) in G. Now let
G'=Sn, and let H' and K' be the
subgroups of G' obtained by embedding G in Sn
according to the two given actions. Show that the actions of G' on the
cosets of H' and K' are not permutation isomorphic but
have the same permutation character.
This exercise is taken from R. M. Guralnick and J. Saxl, "Primitive
permutation characters", pp. 364-367 in Groups, Combinatorics and
Geometry (ed.M. W. Liebeck and J. Saxl), London Math. Soc. Lecture
Notes 165, Cambridge Univ. Press, Cambridge, 1992.
10. Let G be a subgroup of Sn, and k a
positive integer not greater than n. The k-closure
G(k) consists of all permutations in
Sn which preserve all the G-orbits on
k-tuples; that is, all permutations h in Sn
which satisfy
for all i1, ..., ik, there exists
g in G such that
i1g=i1h, ...,
ikg=ikh.
Prove the following:
- G(k) contains G(k+1);
- G(n) = G;
- G is k-transitive if and only if
G(k) = Sn;
- if G is abelian then so is G(2);
- if G is the automorphism group of a graph (acting on the
vertices) then G(2) = G.
See H. Wielandt's lecture notes Permutation Groups through Invariant
Relations and Invariant Functions, Ohio State University 1969 (also
available in his collected works, Volume 1, published by de Gruyter in 1994).
11. An application of the Orbit-Counting Lemma.
-
How many different ways of colouring the faces of a cube with three colours
are there, if two colourings related by a rotation of the cube are counted
as being equal?
-
Same question for edges.
-
Same question for vertices.
12. Let G be a transitive permutation group of prime degree p,
and let P be a Sylow p-subgroup of G. Suppose that
NG(P)=P. Show that G is a
cyclic group of order p, acting regularly. (Hint: Show that the number
of elements not of order p is equal to the order of
Gα, and deduce that Gα is a
normal subgroup of G.)
13. This question should only be attempted with the help of a computer algebra
system such as GAP, otherwise the computations will be rather long!
Let G be a non-abelian simple transitive group of degree 11.
- Show that the Sylow 11-subgroup P of G has order 11,
and that its normaliser has order 55. (You may use the result of the
preceding question, and the fact that a simple permutation group of
degree greater than 2 cannot contain an odd permutation.)
- Show that, unless G is the alternating group A11,
the Sylow 5-subgroup Q of G has order 5, by verifying that
G cannot contain either of the 5-cycles of an element in the
normaliser of P. Show further that
CQ(Q)=Q, by examining which elements of the
symmetric group S11 commute with Q.
- Show that a generator of Q is conjugate in G to its
inverse. What is the cycle structure of a conjugating element x?
- Hence show that the group generated by P, Q and x
is either the alternating group A11 or a 2-transitive
group of order 660. Identify the group G in the latter case
(compare Question 4).
- In the cases where the group has order 660, show that there are only
two choices for an element y satisfying y2=x
and normalising Q and contained in a simple group, up to inversion. If
y is such an element, show that P, Q and y
generate A11 in one case, and a sharply 4-transitive
group H of order 7920 in the other.
14. Investigate similarly the possibilities for a transitive simple group
of degree 7 or 23.
15. This problem is taken from the puzzle page
of METRO, 20 December 2000. First the following question was posed.
Match each of these languages to where they are spoken:
1. Amharic |
A. Brazil |
2. Farsi |
B. Ethiopia |
3. Portuguese |
C. India |
4. Telegu |
D. Iran |
5. Urdu |
E. Pakistan |
The paper then asked:
If the options for this puzzle were given in an entirely random order,
how many of the five pairs of answers would line up correctly in the
same row, averaged over many puzzles? What about if there were ten
options in each column?
16. This question is Enigma 1124 from New Scientist, where you can find
it stated with more detail. It can be solved by a few applications of the
Orbit-Counting Lemma, or more easily by the Cycle Index Theorem.
A stained glass window consists of nine squares of glass in a
3 × 3 array. Of the nine squares, k are red, the rest
blue. A set of windows is produced such that any possible window can be formed
in just one way by rotating and/or turning over one of the windows in the
set. Altogether there are more than 100 red squares in the set. Find k.
17. Let PGL(2,5) denote the group of linear fractional transformations of
the projective line over GF(5).
Show that PGL(2,5) is a subgroup of S6 of order 120.
Hence show that
- PGL(2,5) is isomorphic to S5;
- S6 has an outer automorphism.
18. Let S=Sym(Ω) be the symmetric group on an infinite
set Ω. Show that the number of orbits of
S x ... x S (with k factors, acting
on the disjoint union of k copies of Ω) on the set of
n-sets is equal to the number of choices of k non-negative
integers with sum n. Hence show that this number is
(n+k-1 choose n).
19. Let A be the group of order-preserving permutations of the
rational numbers. Prove that the number of orbits of
A Wr A (in its imprimitive action) on n-sets
is equal to the number of expressions for n as an ordered sum of
positive integers. Hence show that this number is 2n-1
for n > 0.
More generally show that the number of orbits of
A Wr ... Wr A (with k factors)
on n-sets is kn-1
for n > 0.
20. Let G=Sym(Δ) be the symmetric group on an infinite
set Δ, and let Ω be the set of 2-element subsets of
Δ. Then G acts as a permutation group on Ω.
Show that G in this action is oligomorphic, and that the number
of orbits on n-subsets of Ω is equal to the number of
simple undirected graphs with n edges and no isolated vertices.
21. Let C be the Fraissé class consisting of all finite
undirected graphs which have no multiple edges but may have loops (with at
most one loop at each vertex). Let G be the automorphism group of
the corresponding countable homogeneous structure. Prove that the number
of orbits of G on n-tuples of distinct points is equal to
2n(n+1)/2.
22. The weight of a monomial
s1a1+...+snan
in the indeterminates s1,...,sn is defined
to be s1+...+nsn. So, in the cycle index
of a permutation group of degree n, every monomial has weight
n.
Prove that, if Z(G)=F1F2,
then all monomials in Fi have the same weight
ni, where n1+n2=n.
Prove that the cycle index of the symmetric or alternating group is
irreducible over the integers (ignoring the factor of 1/|G|).
23. For each n from 5 to 33 inclusive, or for as many as you can,
find a primitive permutation group of degree n other than
Sn and An.
(Harder!) Show that the only primitive groups of degree 34 are the symmetric
and alternating groups.
Book homepage
|
Permutation groups resources
Peter J. Cameron
14 October 2009.